M:=2;N:=5;
a1:=abs(close-open)/open<0.015;
a2:=count(a1,m)=m;
a3:=ref(o,m)<ref(close,m) and
ref(close,m)/ref(close,m+1)>1+n/100;
a2 and a3;

查看更多大智慧公式,请你访问http://gupiao.onjobs.com.cn/category/3/